In this figure, we take $ϵ=0.05$ and $ω=40.0$⁠. The upper curve represents the exact conical solution for $θ(t)$ and the horizontal solid line is the corresponding WSK conical solution $ac=2.4$⁠. Using the algorithm in section 3, the initial conditions required to produce this exact solution are $a0≡A0=2.3650,a1≡A1=0.0,b2≡b2c=1.4142$ giving $μ=0.1041$⁠. For the lower curve $ac=π2,A0=1.5209,A1=0.0, b2c=2.0$ so that $μ=1.0$⁠.