Abstract
Given a compact convex planar domain with non-empty interior, the classical Neumann’s configuration constant is the norm of the Neumann–Poincaré operator acting on the space of continuous real-valued functions on the boundary , modulo constants. We investigate the related operator norm of on the corresponding space of complex-valued functions, and the norm on the subspace of analytic functions. This change requires introduction of techniques much different from the ones used in the classical setting. We prove the equality , the analytic Neumann-type inequality , and provide various estimates for these quantities expressed in terms of the geometry of . We apply our results to estimates for the holomorphic functional calculus of operators on Hilbert space of the type , where is a polynomial and is a domain containing the numerical range of the operator . Among other results, we show that the well-known Crouzeix–Palencia bound can be improved to . In the case that is an ellipse, this leads to an estimate of in terms of the eccentricity of the ellipse.
1 Introduction
1.1 Double-layer potential
Throughout this article, will denote a compact convex planar domain with non-empty interior. If is the space of continuous functions on the boundary and , then its double-layer potential is the harmonic function
Here is the arclength measure on the rectifiable curve , is the interior of , and is the outer-pointing normal at the boundary point . The equality between the two expressions for above follows from an elementary computation in the case that is sufficiently smooth. In the general case, we interpret as a Borel measurable function on . By convexity of the domain, both the tangent and the normal exist and are continuous at all but a countable number of points , which we will call corners, at which the discontinuity of and amounts to a jump in the argument. In Appendix A we include more details regarding boundaries of planar convex domains, and other facts mentioned below.
The Neumann–Poincaré operator appears in connection with the study of boundary behaviour of the double-layer potential. It is known that given by (1) has a continuous extension to , and we have the representation
where denotes the Neumann–Poincaré integral operator
Here is the probability measure
where can be interpreted as the angle of the aperture at the possible corner at of , is a unit mass at the point , and is the Radon–Nikodym derivative
It is natural to use the convention that if is not a corner. This occurs precisely when assigns no mass to the singleton . We will say that the collection of measures is the Neumann–Poincaré kernel of .
The density has the following useful geometric interpretation. If is not a corner, and is the radius of the unique circle passing through that is tangent to at , then the equality
holds. The radius may degenerate to if is contained in the tangent line to passing through . In that case we see easily that , so (5) still holds. To establish the formula, note that the center of the circle in question is of the form , where the radius of the circle satisfies . Expanding the squares and solving for leads to (5).

Fig. 1
Example domain with corner of angle at , and a circle of radius with center , tangent to at and passing through .
1.2 Neumann’s configuration constant
1.2.1 Real configuration constant
Historically, the Neumann–Poincaré operator has been used to solve the Dirichlet problem of finding a harmonic extension to of a given continuous function on . The extension can be obtained by finding , which solves (2). Indeed, if such an is found, then the extension of to is given by the double-layer potential in (1). This naturally leads to questions of invertibility of the operator appearing on the right-hand side of (2), and consequently to the introduction of the Neumann’s configuration constant, which we shall soon define as the operator norm of acting on an appropriate space. Note that if is the constant function, then we have that , since each is a probability measure. Thus can be naturally defined as a linear mapping on the quotient space . The classical approach is to instead consider as acting on the space of real-valued continuous functions , in which case the corresponding quotient space is endowed with the norm
It is not hard to see that the two above expressions for the norm of the coset are equivalent: they are both equal to half of the length of the interval , the image of . The right-most expression is minimized by choosing to be the mid-point of the image interval. Neumann’s (real) configuration constant is defined as the operator norm of acting on the quotient space :
It is not hard to see that we may let instead act from into the quotient without affecting the operator norm. Since each measure is of unit mass, we have . If
then
where we use the total variation norm (functional norm) on the right-hand side. By varying over the unit ball of and over , we obtain the important relation
This expression for will play a fundamental role in our study.
1.2.2 Neumann’s lemma
From (8) we can immediately deduce that in the case that is a triangle or a convex quadrilateral. Indeed, in those cases one sees from (3) and (4) that if and are corners of (opposing, in the case of the quadrilateral) then and are mutually singular, and so , implying . Neumann’s lemma, which appears initially in Neumann’s book [14], states that the cases of the triangle and quadrilateral are exceptional. For any other type of domain we have the strict inequality . See [17] for a proof of this claim by Schober, and the curious history of incomplete attempts at a valid proof in full generality. Neumann’s lemma implies the invertibility of on , and thus the solvability of the Dirichlet problem on a convex domain , which is not one of the two exceptional cases. The remaining cases can be handled by considering instead powers of . See, for instance, [13, Theorem 3.8], [6, Proposition 7], or the article [16], which contains also an exposition of the double-layer potential and Neumann’s lemma.
At the other extreme, we have if and only if is a disk. This result will be proved in Section 5.
1.3 Complex and analytic configuration constants
1.3.1 Two new configuration constants
In the present article we will discuss certain applications of the double-layer potential to operator theory, which motivate the definition of the complex configuration constant
The difference between (7) and (9) is that the latter is the norm of on the larger space of complex-valued functions. As a consequence, we have . There is a principal difference between the geometric interpretations of the norms in the quotient spaces and . In the former case, as we have already noted, the norm (6) of the coset represented by the real-valued function is equal to half of the length of the image of , this image being an interval on the real line . In the case of complex-valued , the quotient norm
can instead be interpreted as the radius of the smallest disk containing the image of . A crucial difference is that we lose the ability to estimate the norm of the coset by considering the quantities only. This is the essence of why new tools are required to treat this case.
We will also study an analogous analytic constant, which is the norm of the operator restricted to the subspace of analytic functions in . More precisely, we let be the space of functions that are continuous in and analytic in . Each function in has a unique restriction to , and thus can be naturally identified with a subspace of . We define the analytic configuration constant as
The space is not invariant under , but we do have that is the complex conjugate of a function in (in [5, proof of Lemma 2.1] this claim is established for with smooth boundary, but the same argument works in general). Clearly, we have the inequality . We note also that if is the image of under an affine transformation of the plane, then the configuration constants of the two domains are equal. We shall verify this claim in Section 6.
1.3.2 An application to functional calculi
Given an operator on a Hilbert space with numerical range
we are interested in the optimal constant in the inequality
where is an analytic polynomial, and the left-hand side is the operator norm of acting on . More generally, if in (12) is replaced by an arbitrary domain , and if the corresponding inequality holds for some , then we say that is a -spectral set for . Von Neumann’s inequality says that the unit disk is a -spectral set for any contraction , and a result of Okubo–Ando from [15] says that any disk containing is a -spectral set for .
The numerical range is a bounded convex subset of the plane, its closure contains the spectrum of , and it has non-empty interior in the case that is not a normal operator (see, for instance, [10, Chapter 1]). For normal operators, the bound (12) with constant is a consequence of the spectral theorem, and it suffices to take the supremum on the right-hand side over the smaller set . For general , even establishing the existence of a bound as in (12) is a non-trivial task. A result of Delyon–Delyon from [6, Theorem 3] establishes the existence of the bound, and shows that can be chosen depending only on the area and the diameter of . The remarkable work of Crouzeix in [3] establishes that (12) holds with . A subsequent work of Crouzeix and Palencia in [5] improves the estimate to . The Neumann–Poincaré operator appears as an essential tool in all of the mentioned works. The standing conjecture of Crouzeix from [2] is that the bound holds with . This bound is presently known to hold in the case being of dimension 2, and has been established by Crouzeix in [2].
Our interest in the new notions of configuration constants is inspired by a recent work of Schwenninger and de Vries in [18], where bounds for general homomorphisms between uniform algebras and the algebras of bounded linear operators are studied. In Section 6 we will combine their arguments with the methods of Crouzeix–Palencia to obtain the following estimate:
For instance, if is a disk, then , which gives the Okubo–Ando result mentioned above. In [18], Schwenninger and de Vries recovered this result also. The estimate (13) is our motivation for the following investigation of the configuration constants , and , and the relations between them.
1.4 Main results
1.4.1 Relation between the real and complex constants
Consider the situation in Figure 2, where the triangular image of the complex-valued function is contained in a disk of radius , and intersects the boundary circle of the disk in three distinct points. The three-point set is not contained in any open half-circle of the boundary, and it follows from a simple geometric argument (which we shall present in the proofs below) that . However, the sides of the triangular image of are all of lengths strictly less than , and this implies that

Fig. 2
A triangular image of a complex-valued function contained in a disk of radius , with three points on the boundary of a disk.
If such a function lies in the image of the unit ball of under the Neumann–Poincaré operator for some domain that satisfies , then a strict inequality occurs. Our first main result excludes this possibility, and so establishes the simplest possible relation between the real and complex configuration constants.
Theorem 1.The equality
holds for every compact convex domain
with non-empty interior.
It follows that every considered domain has a well-defined configuration constant , which is equal to the operator norm of on , and which can be computed according to the right-hand side of (8). An important consequence of this result is the inequality
which, as we shall soon see, has some interesting consequences.
Theorem 1 doesn’t appear nearly as straightforward to prove as it is to state, and the proof takes up a large portion of the article. However, the only property of the Neumann–Poincaré operator used in the proof is that its integral kernel consists of real-valued measures. In fact, the theorem will be deduced as a corollary of a result, which we call the Three-measures theorem, and which is a general statement regarding the geometry of the space of continuous functions on a compact Hausdorff space . This result, which we discuss and prove in Section 2, puts a restriction on the possible configurations of point sets in the plane, which arise as values of a collection of real-valued functionals on .
1.4.2 Analytic Neumann’s lemma
Note that the above estimate in (14), together with Neumann’s lemma, implies that whenever is not a triangle or a quadrilateral. This can be improved, for we have an analytic version of Neumann’s lemma, in which no exceptional cases occur.
Theorem 2.The strict inequality
holds for every compact convex domain
with non-empty interior.
Our proof of Theorem 2 is much different from the one given by Schober in his proof of the real Neumann’s lemma in [17], but it works also in the real context. At the end of Section 4 we show how our technique leads to a different proof of Neumann’s lemma.
1.4.3 Functional calculus bounds
The following result has already been mentioned above.
Theorem 3.Let
be a bounded linear operator on a Hilbert space
with numerical range
, which has non-empty interior. Then, for every polynomial
, we have
Recall that if the numerical range of an operator has empty interior, then the operator is normal, and so (12) holds with . From this observation and Theorem 2 we obtain that for any fixed operator , the optimal constant in (12) is always strictly smaller than . In fact, we deduce from our results that we have the inequality
with a constant
which depends only on the shape of , and not on the operator itself. We show in Section 5 that no better universal bound can be obtained by means of the analytic configuration constant: for any there exists a “thin” quadrilateral for which we have . However, fixing the dimension of the Hilbert space , one may combine earlier results of Crouzeix to obtain a uniform improvement. The optimal constant in (12) varies with , and we may consider the supremum of these quantities among all operators on a Hilbert space of a fixed dimension . In [4, Theorem 2.2], Crouzeix proved that there exists an operator realizing this supremum. An immediate corollary of his result, Theorem 2 and Theorem 3 is the following.
Corollary 4.For every positive integer
, there exists a constant
for which we have
whenever
is an operator on an
-dimensional Hilbert space, and
is a polynomial.
This improves the Crouzeix–Palencia bound, although by an indefinite amount.
1.4.4 Estimates for the configuration constants
In Section 5 we present also other computations and estimates for the configuration constants. Surprisingly, in the case of an elliptical domain, the configuration constant is computable exactly, and we obtain
where and are lengths of the semi-axes of the ellipse , and is the eccentricity of the ellipse, given by in case that . This fact, together with Theorem 1, estimate (13), and the inequality , has the following consequence.
Corollary 5.Let
be a bounded linear operator on a Hilbert space
with numerical range contained in (or equal to) the ellipse
. Then, for every polynomial
, we have
where
Note that the function is continuous and increasing for , and we have
Hence the estimate in Corollary 5 gets worse as the eccentricity of the ellipse grows, and approaches the Crouzeix–Palencia bound in the limit . On the other hand, as , the eccentricity of the ellipse tends to . The estimate is then close to the conjectured optimal bound and coincides with the Okubo–Ando bound for , in which case the domain is a disk. From this perspective, Corollary 5 may be interpreted as an elliptical generalization of the Okubo–Ando estimate.
For many other types of domains, the exact value of is inaccessible. To help the situation, we establish an integral estimate, which gives an upper bound on in terms of the curvature of , roughly speaking. For a fixed that is not a corner of , recall the definition of in (5), and consider
If is the curvature of at , then is at least as large as the radius of curvature
which is also the radius of the osculating circle at . Geometrically, is the radius of the smallest disk tangent to at , which contains , if such a disk exists, and it is equal to otherwise. The latter case occurs, for instance, if lies on a straight line segment contained in . However, if is sufficiently curved on a segment of , then will be bounded above there. We obtain in such a situation a non-trivial upper bound on .
Theorem 6.With the above notation, we have the estimate
The result implies spectral constant estimates similar to the one in Corollary 5 above. It also generalizes some similar results in the literature. See Section 5 for further details and examples.
1.4.5 An unresolved matter
We have mentioned above that if and only if is a disk. With some additional effort, we will show in Section 5 that the condition also characterizes disks. In this case, we have the equality . It is natural to ask whether other domains exist for which the equality occurs, or if the case of the disk is exceptional.
Question.Do we always have the strict inequality
whenever
is not a disk?
As a consequence of Theorem 2 and the exceptional cases of Neumann’s lemma, we see that the strict inequality holds whenever is a triangle or a quadrilateral. The authors have not been able to confirm that the inequality holds in any other examples.
1.5 Notations
Some of our notation has already been introduced above. For a continuous function defined on a set , we denote by the supremum of over . For cosets of the form we use the convention
with similar convention for real-valued and cosets . A norm without a subscript usually denotes a linear functional norm or a total variation norm of a measure. The distinction will be unimportant and should anyway be easy to deduce from context. We use boldface letters, such as , to denote vectors in , and plain letters, such as , to denote the coordinates.
2 The Three-Measures Theorem
2.1 Definitions of relevant spaces and operators
Theorem 1 will be proved as a corollary of our analysis of three-point configurations
where is an element of a given normed space , and are three bounded linear functionals on . A point configuration of this type has to satisfy certain conditions. For instance, we must have the distance bound
Our principal interest will be in estimating the radius of the smallest disk that contains such a three-point set.
In order to use the tools of functional analysis, we will formulate our problem as one of estimating the norm of an operator between normed spaces. To this end, we use the space of triples of complex numbers, and we equip it with the following norm:
Similarly to our previous notational conventions, we shall set . The quotient norm in the quotient space satisfies
and it has the geometric interpretation adequate to our problem: it is the radius of the smallest disk containing the three point set . Given a normed space and three linear functionals , we introduce the linear operator defined by
With these conventions, each three-point configuration is contained in a disk of radius at most . We want to estimate the operator norm .
2.2 Statement of the theorem
Without any information regarding the space or the functionals , the optimal estimate is
Indeed, we see that we cannot do better by choosing , , and the functionals (scalars) to be the vertices of an equilateral triangle inscribed in the unit circle. For instance,
The sides of the triangle have the common length equal to , and the smallest disk containing the three points is the unit disk itself. Thus, in this case, (19) holds with equality. The estimate holds in general as a consequence of Jung’s theorem, which appeared first in [11], and which in the context of the plane says that any set of diameter is contained in a disk of radius . In our setting , and so the estimate (19) follows from Jung’s theorem.
In our intended application, the role of the space is played by , the Banach space of continuous functions on a compact Hausdorff space , and the functionals are given by integration against real-valued measures
It turns out that the three-point configurations that arise in this way are contained in disks of radius smaller than predicted by Jung’s theorem. The main result of the section is the following.
Theorem 7.Let
be the space of continuous functions on a compact Hausdorff space
, and
be the operator in (
18) defined by three functionals induced by three finite real-valued Borel measures
. Then
It is the “” estimate in (20) that is the critical one. The lower bound “” follows from the definition of the functional norm
We will spend the rest of the section on proving Theorem 7. The outline of the proof is as follows. We will first use duality to formulate the problem in terms of the adjoint operator between the dual spaces. Next, a discretization will help us reduce the dual problem to a finite-dimensional optimization problem. Finally, we will solve the finite-dimensional problem by the use of techniques of convex analysis.
Before proceeding, we remark that the natural generalization of the above theorem to an arbitrary -tuple of real-valued measures is valid. See Theorem 17 below.
2.3 Dual problem
Let us denote by the space equipped with the norm in (17). Then the dual space is the two-dimensional space of three-tuples of complex numbers that satisfy
and the norm on is given by
In the case , the dual space is just the space of finite Borel measures on . The adjoint operator is then given by
and the estimate (20) is equivalent to
Since and , we may rewrite the above inequality into
where
Note that and are real-valued if are real-valued. Theorem 7 is thus a consequence of the following slightly more general statement in which the topological structure of does not play a role.
Proposition 8.Let
and
be two finite real-valued measures on a measurable space
. Then for any complex numbers
we have the inequality
where the norm on the right-hand side is the total variation norm
.
In our next step, we shall simplify the problem further, and show that Proposition 8 can be established by considering finite sets only.
2.4 Discretization
With notations as in Proposition 8, set . Then is a positive finite measure on , and by the Radon–Nikodym theorem we have and , where are bounded real measurable functions on . For a moment, let denote the norm
Then Proposition 8 is equivalent to the inequality
We will say that a function is simple if it only takes on a finite number of distinct values. By standard measure theory, there exist simple measurable real functions , on such that and uniformly on . Clearly . Likewise and and . Thus, if the inequality (24) holds for each pair of simple functions, then it holds for . So it suffices to establish (24) when are simple measurable real functions.
Hence, suppose that are simple measurable real functions on . We can write them as and , where is a measurable partition of , and for all . The inequality in (24) becomes
Writing
and
we see that this becomes
where now are vectors in and denotes the usual -norm on given by
To summarize, to prove Proposition 8 and consequently to prove Theorem 7, it suffices to establish the following discrete result.
Proposition 9.Let
and
. Then for all complex numbers
we have the inequality
This reduction of the problem to the finite-dimensional setting allows us to use the tools of convex analysis.
2.5 Optimization over a convex set
Consider the set
Thus is a compact convex polytope in , and so it has a finite number of extreme points. That is, points of that do not lie in the interior of any line segment in . A well-known theorem of Carathéodory says that each point of a compact convex polytope is a convex combination of its extreme points.
Lemma 10.In order to establish Proposition 9, it suffices to show that the inequality (26) holds for every extreme point of .
Proof.Let us fix
and
. By the homogeneity of the inequality in (
26), we may assume that
Then
and so we may express it as a convex combination of the extreme points of
, namely
where
,
, the pairs
are extreme points of
,
, and
. Note that since
is an extreme point of
, we must have
Since we are assuming that (
26) holds for extreme points, we can estimate
Recalling our normalization in (
28), this is the desired estimate in (
26).
From the above lemma and our sequence of reductions above, it follows that in order to prove Theorem 7 it suffices show that the inequality (26) holds at every extreme point of the polytope . Proposition 11 below characterizes these extreme points by partitioning them into three equivalence classes.
Note that is invariant under the following linear symmetries:
where is any permutation of ,
for any choice of ,
and
Denote by the group generated by these symmetries. As these symmetries are linear automorphisms of , it is clear that leaves invariant the set of extreme points . We say that two extreme points of are -equivalent if there is an element of mapping one of them to the other. Thus the action of on partitions the set of extreme points of into a finite number of equivalence classes. Note that if the inequality (26) holds for some , then it holds also for any point of in the orbit of under the group action of on .
The extreme points of are identified in the following proposition.
Proposition 11.If
, then every extreme point
of
is
-equivalent to one of the pairs
One can readily check that each of the three above pairs really is an extreme point of . We omit the proof, since we do not actually need this fact. In the case that , the same result holds, but only the first kind of pair can arise. Likewise, if , the same result holds, but only the first two types of pairs can arise.
We will prove Proposition 11 in Section 2.6. For now let us see how Theorem 7 follows. In order to verify (26) for all extreme points of , it suffices to verify the inequality for the three pairs of vectors appearing in Proposition 11. This is an easy task. For instance, if is the second pair in Proposition 11, then we have
The inequality for the other two pairs is verified similarly. Then from Lemma 10 we conclude that Proposition 9 holds, from which Theorem 7 follows by the earlier reduction.
It remains to prove Proposition 11.
2.6 Extreme points of the polytope
In the proof of Proposition 11, the group generated by the symmetries (29)–(32) will be extensively used. In particular we will use the property that is an extreme point of if and only if some extreme point of is -equivalent to it. Moreover, the following two observations will be useful to single out.
Lemma 12.If for a pair
there exists two distinct indices
such that
then
is not an extreme point of
.
More generally, if for two distinct indices we have that two of the quantities , and are non-zero and have the same sign, then is not an extreme point of .
Proof.Using the symmetry (
29) we may suppose that
,
. Note that
,
, since
. The same is true for the corresponding coordinates of
. Let
. It is easy to verify that if
is a real number, and
is sufficiently small, then we have
Thus
lies on a line segment inside
, and so is not an extreme point of
.
The more general statement follows by applications of a sequence of symmetries in (29)–(32) to transform satisfying the more general assumption into a point where the first two coordinates of the vectors and are positive.
Lemma 13.If for a pair the vector or has at least three non-zero coordinates, then is not an extreme point of .
Proof.By using symmetries (29)–(31) we may suppose that coordinates are non-zero and positive. If two of the coordinates are positive, then by Lemma 12 we conclude that is not an extreme point of . In the contrary case, two of the coordinates are non-positive. Then again by Lemma 12 and the symmetry (32) the pair is not extreme, and thus neither is , since these two pairs are -equivalent.
We are ready to prove Proposition 11. We denote by the space equipped with the norm given by (25). Recall that the extreme points of the unit ball are the vectors with precisely one non-zero coordinate, this coordinate being equal to .
Proof of Proposition 11.We will split up the proof into three cases, each case corresponding to one of the pairs in the statement of the proposition.
Case 1: At least one of the norms is strictly less than . We will show that in this case is -equivalent to the first pair in the statement of the proposition.
By applying a suitable combination of symmetries (29)–(32), we may suppose that in fact . We claim that must be an extreme point of the unit ball of . For if not, then it lies at the midpoint of a line segment such that for all . Since , by shrinking if necessary, we also have for all . Thus is a line segment in with interior point , contradicting the fact that is extreme.
Likewise, is extreme in the unit ball of . Applying a suitable symmetry, we may suppose that and for some , all the other entries of and being . Since we must have , this implies that actually and . Thus is equivalent to the first pair of vectors listed in the statement of the proposition. This concludes Case 1.
Case 2: We have , and one of the vectors , , or has only one non-zero coordinate. In this case, will be now shown to be -equivalent to the second pair in the statement of the proposition.
Using our symmetries, we may suppose that
. Note that
and
force
the unique real solution
to this equation being
. By Lemma
13,
has only one other non-zero coordinate, and
forces this coordinate to be equal to
. Applying symmetries (
29) and (
30) we conclude that
is
-equivalent to the second pair in the statement. This concludes Case 2.
Case 3: We have , and all of the vectors , and have exactly two non-zero coordinates. We will show that is -equivalent to the third pair in the statement of the proposition.
This case is slightly more complicated than the previous two. As before, we may suppose that and . We claim that and cannot both be equal to zero. If they were, then has four non-zero coordinates, contrary to the assumption. In fact, precisely one of and must be non-zero. If both were non-zero, then since has exactly two non-zero coordinates, we would have and . Then the three quantities , and would be non-zero, and Lemma 12 would imply that is not an extreme point.
By an application of symmetries we may, in addition to
and
, suppose that
,
and
. Since
, we have
,
for some
. Our vectors thus have the following structure:
Recall that has only two non-zero coordinates. Since and , we conclude from the above that . But then , and so . Finally, shows that , and so is -equivalent to the third pair in the statement of the proposition.
3 Proof of Theorem 1
In addition to Theorem 7 from Section 2, we will also need some facts from plane geometry in order to prove Theorem 1. In particular, we will need to discuss the minimum enclosing disk problem appearing in computational geometry.
3.1 Minimal enclosing disk
Let be a compact subset of containing at least two points. Among all closed disks that contain there exists a unique one of minimal radius. We will denote this disk by and call it the minimal disk for . The radius of will be denoted by .
If is minimal for , then the intersection must obviously be non-empty. In fact, this intersection must contain at least two points, and there is also a restriction on the locations of the points in .
Lemma 14.Let be a compact subset of , which contains at least two points. Then the intersection is not contained in any arc of , which has length strictly smaller than half of the circumference of . In particular, if is a two-point set, then and are antipodal on .
Proof.Seeking a contradiction, assume that
is contained in an arc of length strictly less than half of the circumference of
. By translation, rescaling, and rotation of the setting, we may assume that
is the unit disk, and that
is contained in some half-space
By compactness, the distance between the compact sets
and
is positive. It follows that we may translate the disk
in the positive direction of the real axis, and then shrink the radius of the translated disk slightly, and the resulting disk will still contain
, yet be of strictly smaller radius than
. See Figure
3. This contradiction establishes Lemma
14.

Fig. 3
The initial disk is the dashed circle, and we assume that is contained in the black thick arc. Then will be contained in the grey disk, which is obtained from by first translating in the direction of the positive real axis, and then slightly shrinking the translated disk. This contradicts the minimality of .

Fig. 4
The thick arc between and is the smallest containing the compact set . It follows that the shorter arc between the antipodal points an must contain points of .
Lemma 15.Let be a three-point set. If is a closed disk for which , and is not contained in any arc of , which is strictly smaller than half of the circumference of , then .
Proof.Assume, seeking a contradiction, that , and so that is strictly smaller than the radius of . Since is the unique circle passing through the three points , we must have that contains precisely two points. Say but . Lemma 14 implies that and are antipodal on . By translation, rescaling, and rotation, we may assume that is the unit disk, , has non-negative real part and . After these operations, we have that and the circumference of is larger than . Thus by hypothesis, surely is not contained in any arc of of length strictly smaller than . But the shorter of the arcs of that contains is then contained in , and so this arc must have a length smaller than . This is a contradiction, and the lemma follows.
3.2 Reduction to three-point sets
The following simple result on minimal disks makes it possible to apply Theorem 7 to more than three measures.
Lemma 16.Let be a compact subset of containing at least two points. There exists a subset , which contains at most three points and for which . In particular, .
It may be convenient to refer to Figure 4 during the reading of the proof.
Proof.If there are two points in that are antipodal on , then we take to consist of those two points. Clearly . In the case that no pair of antipodal points of are contained in , let be the shortest closed arc of , which contains , and let be the end-points of . By Lemma 14, the length of is strictly larger than half of the circumference of , and so is the longer of the two arcs between and . Let and be points on , which are antipodal to and , respectively. By assumption, . We claim that the shorter of the two open arcs between and must contain points of . If not, then the longer of the two arcs between and would contain in its interior, and this arc has the same length as . A routine compactness argument would lead to a contradiction to the minimality of .
Let , where is any point contained in the shorter open arc between and . Note that any arc containing must contain either or . Then such an arc contains two antipodal points on , and so it has a length that is at least half of the circumference of . By Lemma 15 we conclude that .
3.3 Finalizing the proof
We are finally ready to give a proof of the equality .
Proof.Since
, it will suffice to show the reverse inequality. To this end, we need to show that given
satisfying
, we have that
. Since
is continuous, the image
is a compact subset of
. If
consists of a single point, then
, and the proof is complete. In other case, let
be the minimal disk for
. We use Lemma
16 to obtain a three-point set
for which
(note that if
contains only two points
, then we may pick
arbitrarily to complete
to a three-point set). The geometric interpretation of the quotient norm in
implies that
. Since
is contained in the image of
, there exists
such that
Since
, we may apply Theorem
7 to
,
for
, and conclude that the operator
defined by
has a norm satisfying the bound (
20). With
denoting the norm on
given in (
17), we obtain
The earlier mentioned extension of Theorem 7 to an n-measures theorem is obtained by employing the same argument as in the above proof. The normed space appearing below is defined analogously to the case treated in Section 2.1.
Theorem 17.Let
be the space of continuous functions on a compact Hausdorff space
,
an integer, and
the operator defined by
where
are finite real-valued Borel measures on
. Then
Proof.We use Lemma 16 to pick a three-point subset of for which we have , and apply Theorem 7 as in the preceding proof.
4 Proof of Theorem 2
4.1 Exploiting subsequences
We will argue by contradiction in order to prove Theorem 2. That is, we will assume that there exists a convex domain with , and so that there exists a sequence of functions in , which satisfy
and
We shall see that this leads to a contradiction. The proof technique below is different from the one employed by Schober in [17] in his proof of Neumann’s lemma, and analyticity is used only at the very end of the proof. In fact, we shall remark at the end of the section how our arguments lead to a new proof of Neumann’s lemma that is different from the one in [17].
Thus, for now, we assume merely that , and we will derive certain consequences of (33). In the course of the proof we shall replace the sequence by a subsequence multiple times, and for convenience we will not be changing the subscripts. We may suppose that , and consequently that the images
are contained in a closed disk of radius centred at the origin. For large , this observation and (33) forces there to be points of the image of outside of any disk centred at the origin of radius strictly less than . By exchanging for a unimodular multiple of itself, we may thus assume that there exists a sequence of points in for which we have
Using that the functions are bounded by in modulus, and the positive measures are of unit mass, we obtain
Recall from (3) that denotes the -absolutely continuous part of . The above computation implies that
Compactness of the boundary implies that we may assume convergence of the sequence to some points . The following lemma shows that we may replace in (35) the densities with the density .
Lemma 18.With notations as above, we have
Consequently, after passing to a subsequence, we can ensure that
for almost every
with respect to the measure
.
Proof.Note that whenever
is not a corner of
or any of the points
or
, we have
If
is a disk around
of small radius
, then for large enough
the denominator on the right-hand side above is uniformly bounded from below for
, with exception of a countable set. This shows uniform convergence of
to
for
, again with exception of an at most countable set. Since
, we obtain from (
35) that
Since
is an arc of length that tends to
as the radius
of
tends to
, the last quantity above can be made arbitrarily small by choosing
small enough. This establishes (
36). Basic measure theory now implies that we may pass again to a subsequence and ensure the pointwise convergence
almost everywhere with respect to
.
Out next observation extracts more information from (33). Consider the strips
These strips have a fixed large “length” but shrinking “width”. One such strip is marked in Figure 5. We claim that each one of the strips intersects the images non-trivially for infinitely many indices . For if not, then for some fixed , we would have that for all sufficiently large , which means that the images are entirely contained in , where denotes the closed disk of radius centred at the origin. But if and are sufficiently small positive numbers, then , a disk of radius centred at the point . See Figure 5. Recalling the geometric interpretation of the norm as the radius of the smallest disk containing the image of , we would arrive at a contradiction to (33). Thus every strip contains points in the image of for infinitely many .

Fig. 5
The unit disk in dark grey with the strip removed. The dotted circle containing the dark grey area has a radius slightly smaller than .
Lemma 19.With notations as above, we may pass to a subsequence again, and obtain a new sequence
that converges to some point
, and such that
for some unimodular constant
and for almost every
with respect to the measure
.
Proof.Since each strip intersects the images of for infinitely many , passing to a subsequence and a routine compactness argument produces a sequence convergent to some , for which , with unimodular and lying in the closure of each of the strips . Thus . We therefore merely need to repeat the previous arguments to see that, after passing to a subsequence, we will have for almost every with respect to the measure .
4.2 Proof of Theorem 2
The above arguments are valid for . However, under the assumption of analyticity, the sequence cannot converge to two different constants on two different sets of positive arclength measure. To make this statement precise, we appeal to the classical theory of analytic functions in the (open) unit disk . Here [8, Chapter II] is an excellent reference for the claims made in the following proof.
Proof of Theorem 2.Let be the space of bounded analytic functions in , identified as usual through boundary function correspondence with a weak-star closed subspace of the space of bounded measurable functions on , the dual of the Lebesgue space of functions integrable on with respect to the Lebesgue measure (arclength measure) on . It is well known that a function that vanishes on a subset of positive Lebesgue measure on must vanish identically.
Fix some conformal mapping
. Under the assumption that
,
, the functions
are bounded in modulus by
in
. By Carathéodory’s classical theorem (see, for instance, [
9, Chapter I.3]),
extends to a homeomorphism between
and
. If
, then Lemmas
18 and
19 show that there exist two sets
that have positive arclength measure, such that
and
Since
is convex, the curve
is rectifiable, and general theory of harmonic measures tells us that the sets
and
have positive Lebesgue measure (see [
9, Chapter VI]). Since
is separable and the functions
are uniformly bounded by
in modulus, the usual Helly-type selection process will produce a subsequence of
, which converges in the weak-star topology to some function
. By the above pointwise convergence, we must have
on
and
on
. Then the non-zero function
vanishes on the subset
of positive Lebesgue measure on
. This is a contradiction, which shows that our assumption
must be false. Theorem
2 follows.
4.3 A proof of Neumann’s lemma
We indicate how one may proceed to use our above arguments to obtain a proof of Neumann’s lemma, stating that if and only if is a triangle or a quadrilateral. We need only the following simple geometric observation regarding the densities .
Lemma 20.Fix . Any that is not a corner of and that satisfies is contained in the union of at most two line segments of containing .
Proof.It will suffice to show that all satisfying the above conditions are contained in at most two different tangent lines to . To see this, recall formula (5). The condition gives , and so is contained in the tangent line to at . The tangent line divides the plane into two half-planes, one of which contains . Assume that two different tangent lines, at and , intersect at . They divide the plane into four sectors, and by convexity precisely one of those sectors contains . Now, any line that passes through and the open sector containing must separate . Therefore, it is not a tangent to .
Neumann’s lemma is established as follows. Assume that . From Lemmas 18 and 19 we see that two points exist for which the measures and are mutually singular. From Lemma 20 we deduce that the support of is the union of at most two line segments containing , and the complement of the support of is also a union of at most two line segments. Thus is the union of at most four line segments.
5 Examples
In this section, we compute and estimate the configuration constants for some types of domains.
5.1 Configuration constant of an ellipse
For , let
be the ellipse centred at the origin with semi-axes of lengths and , respectively. It is quite remarkable that the configuration constant can in this case be computed explicitly.
Proposition 21.With the above notation, we have
In order to prove the proposition, our first step is to derive an expression for the density of the Neumann–Poincaré kernel of . The boundary is parametrized by
Here can be replaced by any interval of length . Recalling formula (4) for and setting , , we obtain
Using (37), this formula can be greatly simplified.
Lemma 22.With the notation above, we have
where
The lemma is established by combining (37) and (38), and then using elementary trigonometric identities to simplify the resulting expression.
With this formula in hand, we now evaluate the configuration constant of the ellipse .
Proof of Proposition 21.Using the formulas (
8) and (
39), we obtain
By the periodicity of
, this last expression simplifies to
For the time being, let us assume that
, so
. Using the fact that (
39) is the density of a probability measure for each
, we have
We readily verify that
if and only if
. Therefore
It is clear that this last integral is maximized over
when
. Putting everything together, we deduce that, if
, then
All that remains is to evaluate the integral. Making the substitution
, and exploiting the fact that
, we have
This proves the result in the case when
. The remaining case is obtained by exchanging the roles of
and
.
5.2 Integral estimates
For a general domain, the exact value of is often inaccessible. In this section, we will present a simple estimate that is applicable to domains with a non-flat part of the boundary that leads to an upper bound on .
Assume that we find a Borel measure on such that
If so, then, for every with , we have
which shows that the image of is contained in a disk of radius centred at . Thus,
One approach is to seek a positive measure on satisfying for all . Then
and so .
We will construct the largest non-negative Borel measure on , which satisfies . The construction is based on the geometric interpretation of the density in (5) and the quantity appearing in (15). In order to avoid the need to establish Borel measurability of defined as a supremum of an uncountable family as in (15), we proceed to define it in a slightly different but equivalent way. Namely, it is easy to see that, given , if there exists a closed disk such that and , then there exists one of smallest radius. We denote this radius by . Note that if is not a corner of , then the corresponding disk must be tangent to at . If no disk passing through exists that contains , then we set . This happens, for instance, if is contained in the interior of a line segment in . In particular, for all but a finite number of points of any polygonal domain.

Fig. 6
A domain with two circles corresponding to values and
Lemma 23.The function is lower semicontinuous. In particular, it is Borel measurable.
Proof.Let and let be a sequence in such that . We need to show that . We can suppose that , otherwise there is nothing to prove. Let . Then, replacing by a subsequence, we can suppose that for all . Thus, for each , there exists a closed disk of radius such that and . The sequence of centres of the disks is bounded, so there exists a convergent subsequence . Let be the closed disk with centre and radius . Then we have and . It follows that . As this last inequality holds for all , we deduce that . This completes the proof.
We set
By the above lemma, is a non-negative Borel measure on . For any , we have
To see this, note that if is not a corner and is the radius of the unique circle tangent to at and passing through , then . Therefore, according to (5),
for almost every with respect to arclength measure on . Inequality (41) follows. Although we shall skip a formal proof, we mention also that is in fact the largest measure satisfying for all . This maximality property of is to be interpreted in the following sense: if is any measure satisfying for all , then .

Fig. 7
A quadrilateral domain with .
By our earlier discussion, we obtain the following upper estimate for the configuration constant:
Note that this is precisely the assertion of Theorem 6 stated in Section 1.
We will now mention some consequences. Recall that if is a plane curve of class , then the radius of curvature of is the reciprocal of its curvature.
Corollary 24.If
has a
-boundary of length
, whose radius of curvature is everywhere at most
, then
Proof.In this case, one sees from (15) and (16) that for all , from which the result follows.
This last result was already known. See for example [7, pp. 45–46] and [12, pp. 128–129]. However the proofs in these references are quite different from the one above.
Corollary 25.Consider a convex circular sector
where
and
. Then
Proof.It is obvious that
for
in the curved part of
, and that
elsewhere. Hence
The result now follows from Theorem
6.
5.3 Analytic configuration constants of quadrilaterals
Theorem 2 shows that for every . Here we show by example that may be arbitrarily close to . Figure 7 shows a narrow quadrilateral domain for which this phenomenon occurs.
Proposition 26.For
, let
be the convex hull of
. Then
Proof.Let be a conformal mapping of the interior of onto the unit disk . By Carathéodory’s theorem, extends to a homeomorphism of onto , and so clearly . Post-composing with a suitable automorphism of , we may further suppose that and .
Consider
. Recalling (
3), we have
, where
is the angle of the aperture of
at
, and
is a probability measure on
. It follows that
Likewise
It follows that the diameter of
is at least
, whence
.
Finally, by trigonometry, is related to by , whence . The result follows.
5.4 Configuration constants equal to zero
Recall the estimate (13) from Section 1, which will be proved in the next section. The estimate is strongest if , and in this case we reach the conjectured bound . Unfortunately, the only domain for which we have is a disk, and in this case (13) reduces to the well-known Okubo–Ando bound from [15]. For completeness we give a proof of the statement that if and only if is a disk. More precisely, we have the following.
Proposition 27.Let be a compact convex domain with non-empty interior. The following are equivalent:
- (i)
is a disk,
- (ii)
,
- (iii)
.
Proof.In the case that is a disk, then (5) implies readily that is a constant independent of , and so for every , the measure is a normalized arclength measure on the circular boundary . Then it follows from the definition that is a constant function, and consequently , so . This shows that the implications and hold.
It remains to prove
. Fix a conformal mapping
, where
is the open unit disk and
is the interior of
. The mapping
extends to a homeomorphism of
and
, and so it makes sense to define the probability measures
on
by the equation
where
is a Borel subset of
, and
is the double-layer potential of
. Since
, it follows that for every
and every pair of points
we have, by the change of variables formula, that
As
varies over
,
varies over
, and it follows that
annihilates
. Then the theorem of brothers Riesz (see, for instance, [
8, Exercise 1, Chapter III]) implies that
where
is a function with vanishing non-positive Fourier coefficients. Note that
is real-valued, so the positive Fourier coefficients also vanish, and consequently
. Since
were arbitrary, we conclude that the hypothesis
implies that all the measures
are equal.
The conclusion that is a disk is now a consequence of the geometric formula for in (5). Fix any , which is not a corner. Since the measures are all equal, so are their densities . Then the circles passing through and tangential to at all have the same radius, and so they all coincide with each other. Thus one circle passes through all points . Consequently is a circle, and so is a disk.
6 Application to Numerical Ranges
6.1 Spectral constant estimate
Our principal motivation for the introduction of the analytic configuration constant is the following result that was mentioned in the Section 1 and that we will now prove.
Theorem 28.Let
be a bounded linear operator on a Hilbert space
, and
the closure of the numerical range of
. If
has non-empty interior, then for every
we have
where
is the analytic configuration constant in (
11), and
is the space of continuous functions on
, which are analytic in the interior of
.
Of course, if has no interior, then its convexity forces it to be a line segment. In that case is a normal operator, and the spectral theorem gives us the better estimate , where may be any Borel measurable function on the spectrum . Thus Theorem 28 implies Theorem 3. In what follows, we will assume that has non-empty interior.
Let us make some initial remarks before going into the proof of Theorem 28. In the case is contained in the interior of , then is defined, as usual, through the Dunford–Riesz holomorphic functional calculus. If , then this definition does not work. Nevertheless, if , then it is a standard result of approximation theory that a sequence of analytic polynomials exists, which converges to uniformly on . In the presence of any uniform bound of the form for polynomials , we may then define as the limit of the sequence in the operator norm. Such bounds are known to exists, the strongest known bound being due to Crouzeix and Palencia. Theorem 28 improves this estimate given information about the numerical range of .
Our proof of Theorem 28 combines the argument of Crouzeix and Palencia from [5] with ideas of Schwenninger and de Vries from [18], where bounds for various functional calculi are derived as a consequence of the existence of extremal functions and extremal vectors. Let be an open set in the plane, and be the algebra of bounded holomorphic functions on . Given an operator with contained in , it is elementary that the quantity
is finite. A normal-families argument shows that an exists with for which the supremum above is attained. Any such will be called for an extremal function. If, moreover, a vector with exists for which
then we will say that is an extremal vector, and is an extremal pair. Unless , an extremal vector might not exist, but we will be able to reduce the proof to the finite-dimensional case. The importance of the concept of extremal pairs stems from the following result. We refer the reader to [1, Theorem 4.5] for a proof (see also [18, Proposition 3]).
Lemma 29.Let
be a bounded linear operator, and
be an open neighbourhood of
. Let
be a corresponding extremal pair. If
, then
is orthogonal to
in
:
The next two lemmas will reduce our task to consideration of finite-dimensional Hilbert spaces, in which extremal vectors exist, and will dispose of the problematic set . The first observation is essentially contained in [18, Proposition 9].
Lemma 30.Let
be a compact convex domain with non-empty interior. If for some
the estimate
holds for every polynomial
and every operator
on a finite-dimensional Hilbert space with
contained in the interior of
, then the same estimate with the same constant
holds also for operators
on infinite-dimensional Hilbert spaces with
contained in the interior of
.
Proof.Let
be as above, with
. It suffices to show that
holds for every analytic polynomial
and every
. Note that
is contained in the finite-dimensional subspace
spanned by
, where
is the degree of the polynomial
. If
is the orthogonal projection, then
, where
is an operator on a finite-dimensional Hilbert space. Since
, our hypothesis implies
The lemma follows.
The proof of the next lemma will use affine invariance of the configuration constants. Let us fix , , and an affine mapping . Then is a conformal transformation of with the additional property of taking a line segment of length to a line segment of length , and a circle of radius to a circle of radius . Let be the affine image of under , and recall the formula for the Neumann–Poincaré kernel in (3) and its geometric interpretation. If , is a Borel subset of , and are the arclength measures on and , respectively, then it follows from the properties of listed above that
A consequence is that the Neumann–Poincaré kernels and of the respective domains satisfy
Then a change of variables shows that for any , and it follows that
Armed with these equalities, we make our second observation.
Lemma 31.Assume that the estimate
holds for every polynomial, every compact convex domain
, and every operator
for which
is contained in the interior of
. Then Theorem
28 holds.
Proof.Replacing
by an operator
for some
, we may assume that
lies in the interior of
. Let
, and
Then
is a convex domain that contains
in its interior. By our assumption, for any analytic polynomial
we have
Since
is an affine image of
, we have
. Since this holds for all
, and since
, we may let
to obtain the desired estimate whenever
is an analytic polynomial. The estimate for
follows by density of polynomials in
.
Proof of Theorem 28.By Lemma 31, it will be sufficient to establish the estimate (42) whenever contains in its interior . Moreover, by Lemma 30, we may assume that is an operator on a finite-dimensional Hilbert space . Let and be an extremal pair corresponding to and the operator . If , then (42) certainly holds, so we may assume that .
Let
be a sequence in
such that
and
locally uniformly in
. Then
in operator norm. Set
. It is shown in [
5, Lemmas 2.1 and 2.3] that
and
For each
, we may choose
such that
We now have the following identity:
Let us consider each of the terms in this identity. By the choice of
, we have
Also, from (
43) and the Cauchy–Schwarz inequality,
By Lemma
29, we have
By Lemma
29 again,
. Since the sequence
is certainly bounded (indeed
), we deduce that
Thus, letting
in (
44), we deduce that
Hence
In particular, for every polynomial
with
we have
since
is extremal. This is equivalent to (
42), and so the proof is complete.
Funding
This work has been done during Malman’s visit at Département de mathématiques et de statistique, Université Laval, supported by Simons-CRM Scholar-in-Residence program. Mashreghi’s research was supported by an NSERC Discovery Grant and the Canada Research Chairs program. O’Loughlin was supported by a CRM-Laval Postdoctoral Fellowship. Ransford’s research was supported by an NSERC Discovery Grant.
Acknowledgments
We are grateful to the referee for the careful reading of the paper, and for the suggestions that we used to improve the manuscript.
A Double-Layer Potential on a General Convex Domain
A.1 Convex domains
Let be a compact convex domain in the plane with non-empty interior . We will be making no assumptions regarding smoothness of the boundary . However, convexity itself implies that is a rectifiable simple closed curve with some additional properties.
The orientation of is to be counter-clockwise (i.e., positive), and we use and to denote, respectively, the counter-clockwise and clockwise one-sided convergence of to within . As a consequence of convexity of , the one-sided tangent angles exist at every point , are locally given by
and satisfy
Strict inequality may occur at most at a countable subset of . If it occurs at , then we say that has a corner at . At any point that is not a corner, the tangent angle
is well-defined, and so is the tangent itself. If is any (positively-oriented) parametrization of , and we set at the corners, then the locally defined function is increasing in , and consequently the tangent is continuous at every point that is not a corner of . At a corner, the discontinuity of amounts to a jump of the argument of . We denote by the outward-pointing normal at .
A.2 Double-layer potential
Let denote the interior of . To each we associate the measure on , which for any arc satisfies
Here is any locally defined continuous determination of the argument function on . Non-negativity of follows from convexity of and our choice of positive orientation of . With respect to this orientation, every arc has a start-point and an end-point , and it is easy to see that
In particular, .
The measure is absolutely continuous with respect to arclength on . Indeed, if , is a sequence of arcs of that are shrinking to , and are the corresponding arclengths, then
We use above an appropriate locally defined holomorphic branch of the logarithm. As , the first factor inside the brackets satisfies
while the second factor stays bounded as a consequence of the inequality . Thus
and from elementary measure theory we obtain that is absolutely continuous with respect to . If moreover is not a corner, then it can be shown that
and so in additional to boundedness we even have the convergence
Thus the Radon–Nikodym derivative satisfies
at every , which is not a corner.
A.3 Boundary kernel
The Neumann–Poincaré kernel is the boundary version of the family of measures introduced above. To each point we associate the Borel probability measure on defined by (A.1) for arcs not containing the point . Because , this definition implies that , where can be interpreted as the angle of the aperture at . Indeed, is equal to the increase in the argument of as we traverse one loop around starting and ending at the point , and since is a probability measure, we must have
With the exception of this possible point mass, is otherwise absolutely continuous with respect to arclength. The corresponding Radon–Nikodym derivative is given by
The formula (A.3) is established analogously to (A.2). All in all, the measure can be decomposed as
where is a unit mass at , is the angle of the aperture at (with the convention that if is not a corner), and where the density is given by (A.3).
A.4 Weak-star convergence
We establish now that
in the sense of the weak-star topology on measures. Note that if is a ball of radius centred at , then expressions (A.2) and (A.3) for the densities of and show that
for every . In particular, choosing , we obtain
Since
we see that given for all sufficiently small we will have
Returning to general , we have
On the right-hand side, the first term tends to zero as , the second can be made arbitrarily small by continuity of , the crude estimate and choice of sufficiently small , the third is dominated in modulus by for sufficiently close to , and the fourth is dominated by , which also can be made arbitrarily small by choice of sufficiently small . The desired weak-star convergence follows.
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